1972
DOI: 10.1002/net.3230020103
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Partial orders of dimension 2

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Cited by 158 publications
(59 citation statements)
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“…Using the result by Baker et al [3] we know that such a poset has dimension at most 2. Thus, there are two numberings p and q of the vertices of E * such that a face f is to the left of a face g if and only if p( f ) < p(g) and q( f ) < q(g).…”
Section: Faster Algorithmmentioning
confidence: 92%
“…Using the result by Baker et al [3] we know that such a poset has dimension at most 2. Thus, there are two numberings p and q of the vertices of E * such that a face f is to the left of a face g if and only if p( f ) < p(g) and q( f ) < q(g).…”
Section: Faster Algorithmmentioning
confidence: 92%
“…We use some kind of adjacency matrix to show upper bounds of s G,λ 1 (P2) The right and left boundary of a 1-polygon consists of two parts: one is non-decreasing from top to bottom and the other is non-increasing.…”
Section: Biconvex Graphs and Bipartite Permutation Graphsmentioning
confidence: 99%
“…We can assume without loss of generality that the x-coordinates are distinct and the ycoordinates are distinct [1].…”
Section: Permutation Graphsmentioning
confidence: 99%
“…More generally, any DAG is upward planar if and only if it is a subgraph of a planar st-graph [7]. In the other direction, every planar finite bounded poset must be a lattice [3,5,23]. This implies that a two-dimensional bounded poset that is not a lattice (such as the one on the left of Figure 2) cannot have an upward planar drawing, and that planarity (a crossing-free drawing) and two-dimensionality (realization by a pair of linear orders) are distinct for non-lattice posets.…”
Section: Hasse Diagrams and Upward Planaritymentioning
confidence: 99%