“…Curves of x R p (t) = (x R 1 (t), x R 2 (t)) T and x I p (t) = (x I 1 (t), x I 2 (t)) T of system(12) with the initial values (x R 1 (0), x R 2 (0)) T = (0.5, -0.1) T , (-0.25, 0.35) T , (0.15, -0.45) T and (x I 1 (0), x I 2 (0)) T = (0.4, -0.2) T , (0.2, -0.45) T , (-0.3, 0.1) T 0.01 + 0.03j cos 8t + 0.01k 0.01 + 0.02j sin 2 4t + 0.01k sin 8t, sin 4t + 1 2 i sin 4t +1 10 j cos 4t + 1 20 k sin 2 2t.By computing, T = π 4 , f 1 (x) = f 2 (x) ≤ 0.089, g 1 (x) = g 2 (x) ≤ 0.097,a + 1 08, b + 11 ≤ 0.051, b + 12 ≤ 0.0245, b + 21 ≤ 0.055, b + 22 ≤ 0.0245, c + 11 ≤ 0.023, c + 12 ≤ 0.034, c + 21 ≤ 0.034, c + 22 ≤ 0.025, Q 1 ≤ 0.5, Q 2 ≤ 0.55. So (H 1 ), (H 2 ) and (H 3 ) are satisfied.…”