1980
DOI: 10.1002/9780470133422.ch1
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Photochemistry of Simple Aldehydes and Ketones in the Gas Phase

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Cited by 33 publications
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“…Aliphatic aldehydes exhibit a weak absorption band in the wavelength range 240−360 nm as a result of a dipole forbidden n → π* transition. 5,6 Photolysis of aldehydes can possibly occur through the following pathways:…”
Section: Introductionmentioning
confidence: 99%
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“…Aliphatic aldehydes exhibit a weak absorption band in the wavelength range 240−360 nm as a result of a dipole forbidden n → π* transition. 5,6 Photolysis of aldehydes can possibly occur through the following pathways:…”
Section: Introductionmentioning
confidence: 99%
“…Aliphatic aldehydes exhibit a weak absorption band in the wavelength range 240–360 nm as a result of a dipole forbidden n → π* transition. , Photolysis of aldehydes can possibly occur through the following pathways: RCHO + h ν RH + CO normalR + HCO normalR + CH 3 CHO RCO + normalH Process 1 is the molecular fragmentation channel. Process 2 represents the fragmentation into free radicals (Norrish type I reaction).…”
Section: Introductionmentioning
confidence: 99%
“…One of the main issues is to understand how the multiple bond-breaking steps are temporally correlated and how the available energy is distributed among the fragments. The photodissociation of simple aliphatic ketones at sufficiently high energy is one example in which the two α-CC bonds can break to produce three fragments: two alky radicals and a carbon monoxide molecule. , This so-called Norrish type I α-cleavage reaction is one of the most important photochemical reactions. Being the simplest aliphatic ketone, the photodissociation of acetone in the ultraviolet region has attracted much attention for decades, partly because it is regarded as a prototype for the Norrish type I reaction and partly because of its important roles in atmospheric photochemistry. , At sufficiently high energies, it is energetically possible to break the two equivalent α-CC bonds, and therefore, the “concertedness” of the two-bond breakage had been an issue of concern. Through femtosecond (fs) time-resolved experiments, it has been shown unambiguously that the eliminations of the two methyl groups take place via a stepwise mechanism regardless of the excitation energy. However, detailed dissociation pathways at such high energies in acetone have not been fully elucidated, and controversies still remained in the literature. …”
Section: Introductionmentioning
confidence: 99%