Pipe viscometry of foams

Rheology of Aqueous Foams: a Literature Review of Some Experimental Works

“…On the other hand, wall slip problem is still present, and has been quoted by numerous authors (David and Marsden, 1969;Raza and Marsden, 1967;Beyer et al, 1972;Patton et al, 1983;Hirasaki and Lawson, 1983;Enzendorfer et al, 1995). Experiments made on pipes having different diameters give different results for the same imposed ∆P, i.e.…”

“…This wall slip velocity is due to the existence of a thin liquid film at the walls. Some authors have tried to evaluate this thin film thickness and the wall slip velocity variation with this thickness (Enzendorfer et al, 1995;Thondavadi and Lemlich, 1985). According to Nezhati (1986 and, there is a correlation between this thin liquid film thickness and foam quality, the slip layer thickness being larger for smaller qualities; but as a first approximation, they find this film thickness to be independent of average bubble size.…”

“…There are methods to compute wall slip velocity values from these measurements: Mooney formalism (1931), assuming wall slip velocity is directly proportional to wall shear stress, has been used by these authors and gives no satisfactory results. OldroydJastrzebski method (1967), where wall slip velocity is assumed to be proportional to wall shear stress and inversely proportional to pipe's diameter, has been used by Enzendorfer et al (1995) and gives good results. Thondavadi and Lemlich (1988) have studied foam flow in 3 m long horizontal pipes having diameters varying from 1 to 5 cm.…”

Rheology and convective heat transfer of colloidal gas aphrons in horizontal mini-channels

“…proposed by Economides and co-workers [38,39] and successfully applied to flow of macrofoams. The volume equalized power law relates the volume equalized stress to the volume equalized shear rate as,…”

“…Figure 10 shows the volume equalized shear stress versus the shear rate. Similarly to macroflow of foams [38,39], the CGA data collapses to a single curve with K VE = 0.062, n = 0.588, and a regression coefficient of 0.95.…”