2021
DOI: 10.1016/j.jde.2021.02.030
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Pogorelov type estimates for a class of Hessian quotient equations

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Cited by 13 publications
(9 citation statements)
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“…The last inequality in (3.4) holds because of the estimate (3.3). If one goes back to the proof of [7, Theorem 1.1], he or she would find that for calculations done at a point, the above inequality has nearly same form with (3.5) of [7] except the last term in the RHS -the last term in the RHS of (3.4) is AT 11 (n − 1) coth(c + ) while the one in (3.5) of [7] is A n i=1 T ii . However, the main role of A in the evaluation of each term in (3.5) of [7] is to absorb those negative terms appearing.…”
Section: Proof Of Theorem 11mentioning
confidence: 99%
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“…The last inequality in (3.4) holds because of the estimate (3.3). If one goes back to the proof of [7, Theorem 1.1], he or she would find that for calculations done at a point, the above inequality has nearly same form with (3.5) of [7] except the last term in the RHS -the last term in the RHS of (3.4) is AT 11 (n − 1) coth(c + ) while the one in (3.5) of [7] is A n i=1 T ii . However, the main role of A in the evaluation of each term in (3.5) of [7] is to absorb those negative terms appearing.…”
Section: Proof Of Theorem 11mentioning
confidence: 99%
“…If one goes back to the proof of [7, Theorem 1.1], he or she would find that for calculations done at a point, the above inequality has nearly same form with (3.5) of [7] except the last term in the RHS -the last term in the RHS of (3.4) is AT 11 (n − 1) coth(c + ) while the one in (3.5) of [7] is A n i=1 T ii . However, the main role of A in the evaluation of each term in (3.5) of [7] is to absorb those negative terms appearing. Since, in our setting here, T ii (x 0 ) can be controlled at x 0 and (n − 1) coth(c + ) is a constant (which will not break the role of A), with the help of properties of σ k -operator and structure equations listed in Section 2, our Pogorelov type estimates in Theorem 1.1 follows by using a similar argument (with necessary modifications 6 ) to the rest part of the proof of [7,Theorem 1.1].…”
Section: Proof Of Theorem 11mentioning
confidence: 99%
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