Operator Algebras, Operator Theory and Applications
DOI: 10.1007/978-3-7643-8684-9_12
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Poly-Bergman Projections and Orthogonal Decompositions of L 2-spaces Over Bounded Domains

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Cited by 18 publications
(23 citation statements)
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“…Since BU,j=CtrueB̃U,jC, one concludes that is necessary and sufficient for . It has been shown [, Theorem ], for every positive integer j , that in the unit disk case and remain valid with Kj=0 and trueK̃j=0.Theorem For every positive integer j , the following formulas hold : leftBD,jleft=leftI(SD)j0.16em(Sdouble-struckD*)j,leftBD,jleft=leftI(Sdouble-struckD*)j0.16em(SD)j.Furthermore, if k is a positive integer then BD,jBD,k=Pjk, where Pjk is the orthogonal projection of L2(double-struckD) onto the jk finite dimensional space given by span zlz¯s:l=0,...,k1;0.222222ems=0,...,j1.…”
Section: Poly‐bergman Spaces and Singular Integral Operatorsmentioning
confidence: 99%
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“…Since BU,j=CtrueB̃U,jC, one concludes that is necessary and sufficient for . It has been shown [, Theorem ], for every positive integer j , that in the unit disk case and remain valid with Kj=0 and trueK̃j=0.Theorem For every positive integer j , the following formulas hold : leftBD,jleft=leftI(SD)j0.16em(Sdouble-struckD*)j,leftBD,jleft=leftI(Sdouble-struckD*)j0.16em(SD)j.Furthermore, if k is a positive integer then BD,jBD,k=Pjk, where Pjk is the orthogonal projection of L2(double-struckD) onto the jk finite dimensional space given by span zlz¯s:l=0,...,k1;0.222222ems=0,...,j1.…”
Section: Poly‐bergman Spaces and Singular Integral Operatorsmentioning
confidence: 99%
“…Let U denotes a non‐empty domain and define the singular integral operators acting on the space L2(U) SU,jf(z):=(1)j|j|πU(wz)j1(w¯z¯)j+1f(w)dA(w),jdouble-struckZ±.In [, Corollary ] and in [, Corollary 2.9.1] it is proved that SD,j=(Sdouble-struckD)jandSD,j=(SD*)j,jdouble-struckZ+.For every non‐zero integer j , denote by Sj the singular integral operator SC,j. By Lebesgue's dominated convergence Theorem, for every positive integer j , one obtains that Sj=slimnSnD,j=slimn(SnD)j=SjandSj=Sj*=(S*)j.It's well known that the operator S is unitary, e.g. the latter follows from the Mikhilin symb...…”
Section: Poly‐bergman Spaces and Singular Integral Operatorsmentioning
confidence: 99%
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