2015
DOI: 10.1007/s00208-015-1353-2
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Pólya–Vinogradov and the least quadratic nonresidue

Abstract: It is well-known that cancellation in short character sums (e.g. Burgess' estimates) yields bounds on the least quadratic nonresidue. Scant progress has been made on short character sums since Burgess' work, so it is desirable to find another approach to nonresidues. In this note we formulate a new line of attack on the least nonresidue via long character sums, an active area of research. Among other results, we demonstrate that improving the constant in the Pólya-Vinogradov inequality would lead to significan… Show more

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Cited by 13 publications
(25 citation statements)
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“…One unlikely but currently plausible 'obstruction' to establishing this unconditionally is the possibility that χ(p) = 1 for all primes p q c , in which case c 1 , c 2 , c 3 ≫ c, or indeed if χ is 1-pretentious for the primes up to q. 1 Inspired by connections highlighted in [2,7,20] we show that improving any one of these bounds will, more-or-less, improve the others.…”
mentioning
confidence: 79%
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“…One unlikely but currently plausible 'obstruction' to establishing this unconditionally is the possibility that χ(p) = 1 for all primes p q c , in which case c 1 , c 2 , c 3 ≫ c, or indeed if χ is 1-pretentious for the primes up to q. 1 Inspired by connections highlighted in [2,7,20] we show that improving any one of these bounds will, more-or-less, improve the others.…”
mentioning
confidence: 79%
“…Following an idea from [2], Proposition 3 has the following consequence for quadratic non-residues: 2 Corollary 2. Fix ∆ ∈ ( 2 π , 1).…”
Section: Connections Between Different Sums Of Charactersmentioning
confidence: 99%
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“…We expect this to be true for smaller values of N although this problem is much less understood. In the special case M = 0, the Generalized Riemann Hypothesis (GRH) implies that (1.3) 0<n N χ(n) N 1/2 q o (1) , which is nontrivial provided N q ε and is essentially optimal. Although the conditional bound (1.3) on the GRH is well-known, see for example [18,Section 1]; it may not be easy to find a direct reference, however it can be easily derived from [12,Theorem 2].…”
Section: Introductionmentioning
confidence: 99%
“…It is a fun exercise to construct a family of completely multiplicative functions f : Z → [−1, 1] for which (1.1) fails. 1 For our application, however, we will only need to compare the two means in the situation that both x and |M f (x)| are large, and in this case we will show that (1.1) does hold. More precisely: It would be interesting to find a more explicit relationship between the two means which holds even when they are small.…”
Section: Introductionmentioning
confidence: 99%