It is well known that, although the category of topological spaces is not cartesian closed, it possesses many cartesian closed full subcategories, e.g.: (i) compactly generated Hausdorff spaces; (ii) quotients of locally compact Hausdorff spaces, which form a larger category; (iii) quotients of locally compact spaces without separation axiom, which form an even larger one; (iv) quotients of core compact spaces, which is at least as large as the previous; (v) sequential spaces, which are strictly included in (ii); and (vi) quotients of countably based spaces, which are strictly included in the category (v).We give a simple and uniform proof of cartesian closedness for many categories of topological spaces, including (ii)-(v), and implicitly (i), and we also give a self-contained proof that (vi) is cartesian closed. Our main aim, however, is to compare the categories (i)-(vi), and others like them.When restricted to Hausdorff spaces, (ii)-(iv) collapse to (i), and most non-Hausdorff spaces of interest, such as those which occur in domain theory, are already in (ii). Regarding the cartesian closed structure, finite products coincide in (i)-(vi). Function spaces are characterized as coreflections of both the Isbell and natural topologies. In general, the function spaces differ between the categories, but those of (vi) coincide with those in any of the larger categories (ii)-(v). Finally, the topologies of the spaces in the categories (i)-(iv) are analysed in terms of Lawson duality.MSC (2000): 54D50, 54D55, 54C35, 06B35.Lemma 2·1. For X exponentiable, the evaluation mappingProof. The transpose of E is the identity map on [X ⇒ Y ], hence continuous, and thus E is continuous since X is exponentiable.Lemma 2·2. For X exponentiable, the exponential topology on C(X, Y ) is uniquely determined.Proof. Suppose that [X ⇒ Y ] and [X ⇒ Y ] are C(X, Y ) endowed with topologies that satisfy the properties of an exponential. By Lemma 2·1 the evaluation map E : [X ⇒ Y ] × X → Y is continuous, and then the identity function on C(X, Y ) from [X ⇒ Y ] to [X ⇒ Y ] is continuous since the latter is an exponential. Reversing the roles of [X ⇒ Y ] and [X ⇒ Y ] gives continuity of the identity in the reverse direction.In light of the preceding observation we denote by [X ⇒ Y ] the set C(X, Y ) of continuous maps endowed with the exponential topology.Lemma 2·3. For X exponentiable and g ∈ C(Y, Z), the mapis continuous by Lemma 2·1, and thus its transpose, which one sees directly to be [X ⇒ g], is continuous.It follows from the preceding that every exponentiable X gives rise to a functor [X ⇒ ·] : Top → Top defined by Y → [X ⇒ Y ] and g → [X ⇒ g]. One observes directly from the fact that [X ⇒ Y ] is an exponential that this functor is right adjoint to the functor · × X. Lemma 2·4. The product of two exponentiable spaces is exponentiable.Proof. Let X 1 and X 2 be exponentiable spaces. Then for all spaces A, one has bijections. Hence the exponential topology on C(X 1 , [X 2 ⇒ Y ]) induces an exponential topology on C(X 1 × X 2 , Y ).Given a fa...