2009
DOI: 10.1007/s00025-009-0001-0
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Powers of Rational Numbers Modulo 1 Lying in Short Intervals

Abstract: Let p > q > 1 be two coprime integers. We construct some positive numbers ξ such that the numbers ξ(p/q) n , n = 0, 1, 2, . . . , modulo 1 all lie in a short interval. Our results imply, for instance, that there exist three positive real numbers ξ, ζ, τ such that the inequalities ||ξ(5/3) n || < 2/5, ||ζ(5/3) n || > 1/10 and ||τ (3/2) 2n || < 14/45 hold for each integer n 0. Mathematics Subject Classification (2000). Primary 11J71; Secondary 11B99.

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Cited by 4 publications
(5 citation statements)
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“…For an overview see [62]; recent contributions are e.g. due to Akiyama, Frougny and Sakarovitch [8,9], Dubickas [28,29] and Kaneko [42,43].…”
Section: Introduction and Statement Of Resultsmentioning
confidence: 99%
“…For an overview see [62]; recent contributions are e.g. due to Akiyama, Frougny and Sakarovitch [8,9], Dubickas [28,29] and Kaneko [42,43].…”
Section: Introduction and Statement Of Resultsmentioning
confidence: 99%
“…has a solution α = 0 for any fixed odd p ≥ 3. As remarked in [11], it follows from ( 16) that the bound in ( 18) cannot be improved to p −1 − 4p −3 < τ (p/1). Finally, the bound from Theorem 3.12 can be slightly improved for q odd with a similar method.…”
Section: mentioning
confidence: 89%
“…It would be nice to have cardinality equal to |R| instead of greater |Z| on the right hand sides in (11), (12). If we assume the continuum hypothesis to be true (which is known to be undecidable due to P. Cohen), then indeed we may make this replacement.…”
Section: mentioning
confidence: 99%
“…Furthermore, Dubickas also proved that for coprime p > q > 1, there exists ξ > 0 such that {ξ(p/q) n } lies in a short interval of [0, 1]. In particular, his work implies that {ξ(3/2) 2n } < 14/45 [5].…”
Section: Related Workmentioning
confidence: 96%

On the Uniformity of $(3/2)^n$ Modulo 1

Neeley,
Taylor-Rodriguez,
Veerman
et al. 2018
Preprint