2015
DOI: 10.1134/s0001434615050259
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Probability distribution for a hard liquid

Abstract: We obtain a distribution of Fermi-Dirac type for a hard liquid at temperatures less than the Frenkel temperature T F for P ≥ 0 and Z ≥ 0. For the van der Waals model, one has T F = (3 3 /2 5 )T c .

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Cited by 4 publications
(5 citation statements)
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“…Substituting the obtained relation N(a) in formula (17), we can find the dependence E(a), and with it the pressure P (a), by using the relation E = (γ + 1)P V .…”
Section: Resultsmentioning
confidence: 99%
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“…Substituting the obtained relation N(a) in formula (17), we can find the dependence E(a), and with it the pressure P (a), by using the relation E = (γ + 1)P V .…”
Section: Resultsmentioning
confidence: 99%
“…This corresponds to the passage from negative pressures to positive ones. This picture naturally arises in the Van-der-Waals formulas [17]- [18]. Thus, the Bose particles and the Fermi particles are positioned in different parts of the -P,Z-diagram of Hougen and Watson (in it, P is the pressure, Z = P V /NT is the compressibility factor, V , the volume, N, the number of particles, T , the temperature): the Bose particles are in the positive domain, while the Fermi particles are in the negative one.…”
Section: A Bose Statistics Fermi Statistics In Hougen-watson Diagrams...mentioning
confidence: 96%
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“…This corresponds to the transition from negative pressures to positive pressures. In the van der Waals formulas [44], [45], such a picture is rather natural. Thus, the fermions and bosons are located in different quarter on the Hougen-Watson PZ-diagram (P is the pressure, Z = P V /(NT ) is the compressibility factor, where V is the volume, N is the number of particles, and T is the temperature): the bosons are in the negative domain and the fermions are in the positive domain.…”
Section: A Bose Statistics and Fermi Statistics In The Hougen-watson ...mentioning
confidence: 99%