2011
DOI: 10.1103/physrevc.84.044620
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Probing the density dependence of the symmetry energy via multifragmentation at subsaturation densities

Abstract: Symmetry energy for asymmetric nuclear matter at subsaturation densities was investigated in the framework of an isospin-dependent quantum molecular dynamics model. A single ratio of neutrons and protons is compared with the experimental data of Famiano et al. [Phys. Rev. Lett. 97, 052701 (2006)] We have also performed a comparison for the double ratio with experimental as well as different theoretical results of Boltzmann-Uehling-Uhlenbeck in 1997, Isospin-dependent Boltzmann-Uehling-Uhlenbeck in 2004, Boltzm… Show more

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Cited by 41 publications
(40 citation statements)
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“…The MST method has been quite successful in explaining certain fragmentation observables such as charge distribution of emitted fragments [22,26], single and double yield ratio of neutrons to protons [6,7], while fails to describe some important detail in the production of free nucleons, light and heavy charged particles [22,[26][27][28]. The failure results are summarized as follow: (1) Yield of Z = 1 is overestimated, while Z = 2 is underestimated.…”
Section: Introductionmentioning
confidence: 99%
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“…The MST method has been quite successful in explaining certain fragmentation observables such as charge distribution of emitted fragments [22,26], single and double yield ratio of neutrons to protons [6,7], while fails to describe some important detail in the production of free nucleons, light and heavy charged particles [22,[26][27][28]. The failure results are summarized as follow: (1) Yield of Z = 1 is overestimated, while Z = 2 is underestimated.…”
Section: Introductionmentioning
confidence: 99%
“…The most commonly and widely used algorithm depends on the spatial and momentum coordinates of the nucleons, is known as minimum spanning tree (MST) algorithm [7,13,22]. According to this method, two nucleons will undergo the cluster formation if the relative distance (|R i − R j |) and relative momentum (|P i − P j |) between the nucleons is less than 3.5-4 fm and 250-268 MeV/c, respectively.…”
Section: Introductionmentioning
confidence: 99%
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“…The symmetry energy coefficient plays a key role, not only in nuclear physics, such as the dynamics of heavy-ion collisions induced by radioactive beams and the structure of exotic nuclei near the nuclear drip lines [1][2][3][4][5][6], but also a number of important issues in astrophysics, such as the dynamical evolution of the core collapse of a massive star and the associated explosive nucleosynthesis [7][8][9][10][11][12][13]. In the global fitting of the nuclear masses in the framework of the liquid-drop mass formula, the symmetry coefficient a sym of finite nuclei enters as a mass-dependent phenomenological parameter [14][15][16][17][18].…”
Section: Introductionmentioning
confidence: 99%