“…By removing from π the digit 8 (or the digit 7) and standardizing, we get ∇ * 8 (π) = τ = [3, 5, 1, 4, 6, 2, 7] ∈ K 7 . This implies the existence of a regent of σ (for example [5,1,3,6,2,8,4,7] The permutations π ∈ K n which have no regents have a special structure. An example for such an element is π = [7, 5, 8, 6, 2, 4, 1, 3, 10, 12, 9, 11] ∈ K 12 .…”