2002
DOI: 10.1002/jgt.10068
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Proof of a conjecture on irredundance perfect graphs

Abstract: Let ir(G) and (G) be the irredundance number and the domination number of a graph G, respectively. A graph G is called irredundance perfect if ir(H ) ¼ (H ), for every induced subgraph H of G. In this article we present a result which immediately implies three known conjectures on irredundance perfect graphs. ß

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Cited by 3 publications
(3 citation statements)
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“…Moreover, Theorem 4 implies Theorems 1, 2 and 3. [18,19]) If a graph G does not contain the graphs P 6 and G 1 , G 4 in Fig.1 as induced subgraphs, then G is an irredundance perfect graph.…”
Section: Summary Of Known Results On Irredundance Perfect Graphsmentioning
confidence: 99%
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“…Moreover, Theorem 4 implies Theorems 1, 2 and 3. [18,19]) If a graph G does not contain the graphs P 6 and G 1 , G 4 in Fig.1 as induced subgraphs, then G is an irredundance perfect graph.…”
Section: Summary Of Known Results On Irredundance Perfect Graphsmentioning
confidence: 99%
“…Conjecture 3 (Puech [16]) Every (P 6 , G 3 , G 4 )-free graph is irredundance perfect. [20]. Laskar and Pfaff also obtained a number of interesting results on irredundance perfect graphs.…”
Section: Conjecture 2 (Faudree Favaron and LImentioning
confidence: 95%
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