2022
DOI: 10.1002/adpr.202200094
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Propagable Optical Vortices with Natural Noninteger Orbital Angular Momentum in Free Space

Abstract: Light beams with optical vortices can propagate in free space only with integer orbital angular momentum. Herein, this scientific consensus theoretically and experimentally is upheaved by proposing light beams carrying natural noninteger orbital angular momentum. These peculiar vortex beams are unique solutions to the Helmholtz equation, which possesses optical vortices with topological charges of l + 0.5, where l is an integer. During propagation in free space, their amplitudes and vortex phases with noninteg… Show more

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Cited by 15 publications
(16 citation statements)
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“…The stability of these unique vortex beams is dependent on the interaction between the vortex phase and the polarization of the fractional‐order VVB. [ 12 ] In the absence of both, the fractional‐order VVB and vortex beam with a noninteger topological charge cannot propagate individually in free space. However, it is unclear as to why does the middle state of a light beam exists naturally in free space.…”
Section: Resultsmentioning
confidence: 99%
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“…The stability of these unique vortex beams is dependent on the interaction between the vortex phase and the polarization of the fractional‐order VVB. [ 12 ] In the absence of both, the fractional‐order VVB and vortex beam with a noninteger topological charge cannot propagate individually in free space. However, it is unclear as to why does the middle state of a light beam exists naturally in free space.…”
Section: Resultsmentioning
confidence: 99%
“…The first is a vortex beam that possesses an optical vortex with a topological charge of ±0.5, in addition to a polarization state of an m + 0.5‐order VVB (see Equation ()); and the second is a vortex beam that has a constant polarization state, namely, a ±0.5‐order VVB, but an optical vortex with an arbitrary topological charge of l + 0.5 (see Equation ()). [ 12,13 ] E m + 0.5 = exp ( ± i 0.5 φ ) [ cos [ ( m + 0.5 ) φ + β ] sin [ ( m + 0.5 ) φ + β ] ] $$E_{m + 0.5} = exp \left(\right. \pm i 0.5 \varphi \left.\right) \left[\right.…”
Section: Resultsmentioning
confidence: 99%
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