1968
DOI: 10.1121/1.1911103
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Propagation of Transient Sound Signals into a Viscous Fluid

Abstract: An arbitrary excitation of the plane x = 0 sends sound signals into the half-space x > 0 occupied by the viscous fluid. The governing third-order partial differential equation is solved exactly usi-•g the Laplace transform on time and the sine transform on space. New expressions for the most general solution are derived. The specific inputs considered in detail are the Dirac delta function, the Heaviside unit function, a decaying exponential, and a sinusoidal excitation. The final expressions are given in the … Show more

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Cited by 10 publications
(7 citation statements)
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“…In 1957 Hanin presented a solution to the above problem although he had great difficulties since the model did not lead to a finite value for the phase velocity at high frequencies and consequently, a wavefront could not be found and the problem was ill-posed. [11][12][13][14][15][16][17][18] The Maxwell model for dissipative fluids, however, yields a well-posed problem and for future use we here give the expression for the phase velocity for the case of a single relaxation process 12…”
Section: Exp͓i͑tϫkx͔͒d ͑5͒mentioning
confidence: 99%
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“…In 1957 Hanin presented a solution to the above problem although he had great difficulties since the model did not lead to a finite value for the phase velocity at high frequencies and consequently, a wavefront could not be found and the problem was ill-posed. [11][12][13][14][15][16][17][18] The Maxwell model for dissipative fluids, however, yields a well-posed problem and for future use we here give the expression for the phase velocity for the case of a single relaxation process 12…”
Section: Exp͓i͑tϫkx͔͒d ͑5͒mentioning
confidence: 99%
“…[10][11][12][13][14][15][16] In terms of analytic function theory this corresponds to application of Jordan's lemma which can be related to the Tauberian theorem also known as the initial value theorem. 11,[15][16][17] What all this means is that in order to get a picture of the solution for short times, that is, at the wavefront, one has to look at the behavior of the integrand for high frequencies. 11 However, this means, from Eq.…”
Section: Exp͓i͑tϫkx͔͒d ͑5͒mentioning
confidence: 99%
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