“…We may shrink each and, in particular, we may assume that admits a smooth compactification such that the complement is a simple normal crossing divisor. Using [Shi11b, Theorem 4.3], [KL81, Theorem 2], and the same argument of [Cre87, Corollary 4.13], one can show that some power is geometrically trivial, i.e. its underlying overconvergent isocrystal is trivial.…”