2019
DOI: 10.1103/physreva.99.022121
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Quantum particle in a split box: Excitations to the ground state

Abstract: We discuss two different approaches for splitting the wavefunction of a single-particle-box (SPB) into two equal parts. Adiabatic insertion of a barrier in the center of a SPB in order to make two compartments which each have probability 1/2 to find the particle in it is one of the key steps for a Szilard engine. However, any asymmetry between the volume of the compartments due to an offcenter insertion of the barrier results in a particle that is fully localized in the larger compartment, in the adiabatic lim… Show more

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Cited by 7 publications
(7 citation statements)
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“…The number of times the agent chooses an action per protocol is given by N t , and the time-step is therefore dt = T /N t . The environment that the agent acts in is the quantum mechanical SPB, with initial state |c 1 | 2 = 1 and |c n>1 | 2 = 0, and time evolution given by the Schrödinger equation i∂ t |ψ(t) = H(t) |ψ(t) , which we solve as in [25]. The sequential process for one episode is then 1.…”
Section: Dql Resultsmentioning
confidence: 99%
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“…The number of times the agent chooses an action per protocol is given by N t , and the time-step is therefore dt = T /N t . The environment that the agent acts in is the quantum mechanical SPB, with initial state |c 1 | 2 = 1 and |c n>1 | 2 = 0, and time evolution given by the Schrödinger equation i∂ t |ψ(t) = H(t) |ψ(t) , which we solve as in [25]. The sequential process for one episode is then 1.…”
Section: Dql Resultsmentioning
confidence: 99%
“…The initial state is therefore given by |c 1 (0)| 2 = 1, and the goal is to construct a protocol α(t), which brings us to a final state where |c 1 (T )| 2 = |c 2 (T )| 2 = 1/2, where T is the duration of the protocol. More details on how the instantaneous eigenstates are calculated, and how the time evolution of the total wave function is numerically solved, is given in [25].…”
Section: Single-particle-boxmentioning
confidence: 99%
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“…Ele mostrou que, se uma parede divisória é introduzida muito lentamente (aproximação adiabática), a partícula sempre será encontrada no interior da parte maior após a divisória ser introduzida completamente, inviabilizando assim a discussão da não localidade [29][30][31]. V. B. Sφrdal e J. Bergli [32] contornaram o problema da assimetria mostrando que uma introdução assimétrica e não adiabática da parede divisória pode conduzir a probabilidades iguais (50%) de encontrar a partícula em uma das partes. S. J. van Enk [33] considerou o caso de duas caixas idênticas, com uma partícula no estado fundamental em cada caixa.…”
Section: Conclusões E Considerações Finaisunclassified