1995
DOI: 10.1016/0166-8641(95)00009-6
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Quasi-measures and dimension theory

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Cited by 24 publications
(17 citation statements)
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“…Define a quasi-state η on C(∆) by η(H) := ζ τ (Φ * H). The WheelerShakhmatov Theorem [26], [44] implies that every quasi-state on a normal topological space (and hence on any metric space) of covering dimension ≤ 1 is linear. Hence η is linear.…”
Section: Symplectic Quasi-states On Surfacesmentioning
confidence: 99%
“…Define a quasi-state η on C(∆) by η(H) := ζ τ (Φ * H). The WheelerShakhmatov Theorem [26], [44] implies that every quasi-state on a normal topological space (and hence on any metric space) of covering dimension ≤ 1 is linear. Hence η is linear.…”
Section: Symplectic Quasi-states On Surfacesmentioning
confidence: 99%
“…Later we will show that there are situations when measures are nowhere dense in the space of all topological measures on X. A positive topological measure has a (necessarily unique) extension to a regular Borel measure on X if and only if for any open sets U and V we have µ(U ∪ V ) ≤ µ(U ) + µ(V ) (see [19]), while for a signed topological measure the condition for extension to a measure is µ(U ) + µ(V ) = µ(U ∪ V ) + µ(U ∩ V ) (see [11]). Remark 1.1.…”
Section: Ii) µ(U ) = Sup{µ(c) : C ⊆ U C ∈ C(x)} For All U ∈ O(x)mentioning
confidence: 99%
“…Work on the theory of topological measures and dimension theory initiated by R. Wheeler, and continued by D. Shakmatov, D. Fremlin, and D. Grubb, describes a very different relationship between measures and topological measures on a space of dimension not greater than 1. See [19], [18], [10] or [12] (a more general result). …”
Section: Proof Of Theorem 33 Let µ Be a Simple Topological Measure mentioning
confidence: 99%
“…Then µ f extends uniquely to a Borel measure on R (all topological measures on one-dimensional spaces extend uniquely to regular Borel measures, cf. [14]). Hence we have the definition The integrals (with respect to topological measures), and hence topological measures, were shown in [1] to be uniformly continuous.…”
Section: Topological Measuresmentioning
confidence: 99%
“…The circle is one-dimensional and hence all topological measures extend to regular Borel measures (cf. [14]). Accordingly T * is homeomorphic to the circle, establishing the assertion.…”
Section: If C ∈ C(x) and A ∈ A(c) Let A *mentioning
confidence: 99%