2009
DOI: 10.1119/1.3246467
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Radial Motion of Two Mutually Attracting Particles

Abstract: A pair of masses or opposite-sign charges released from rest will move directly toward each other under the action of the inverse-distance-squared force of attraction between them. An exact expression for the separation distance as a function of time can only be found by numerically inverting the solution of a differential equation. A simpler, approximate formula can be obtained by combining dimensional analysis, Kepler's third law, and the familiar quadratic dependence of distance on time for a mass falling n… Show more

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Cited by 5 publications
(2 citation statements)
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“…Your first inclination may be to fire a projectile vertically (i.e., radially) from the planet's surface. The projectile's path is thus a degenerate orbit [4] with periapsis distance r peri = 0 and specific angular momentum h P = 0. There are two questions we shall answer for this case:…”
Section: Case Study: a Vertically Launched Projectile Colliding With ...mentioning
confidence: 99%
“…Your first inclination may be to fire a projectile vertically (i.e., radially) from the planet's surface. The projectile's path is thus a degenerate orbit [4] with periapsis distance r peri = 0 and specific angular momentum h P = 0. There are two questions we shall answer for this case:…”
Section: Case Study: a Vertically Launched Projectile Colliding With ...mentioning
confidence: 99%
“…As long as ε < 0, which requires k < 5 from equation (3), it will subsequently fall into the planet with an impact directly below the collision point. Such bound radial trajectories are discussed in [4].…”
Section: Effects Of Increasing a Horizontal Projectile's Launch Speedmentioning
confidence: 99%