“…b) Whenever arcsin(b/c) ≈ π/4, one also has arcsin(a/c) ≈ π/4, and both triples may either fall into two different subintervals of the exact lookup table, which can help reduce the value k (since they share a common hypotenuse), or fall into the same subinterval, which can help find a better corrective term. Hence the first step of PPT generation using the Barning-Hall tree is the following: multiplying the matrices in Equation (4) by the root (3, 4, 5) taken as a column vector, one gets the three new PPTs (5,12,13), (15,8,17), and (21,20,29), and their symmetric counterparts (12,5,13), (8,15,17), and (20,21,29). In the following, note that we always consider the "degenerated" PPT (0, 1, 1), because it gives us an exact corrective term for the first table entry, without making the LCM k grow.…”