1997
DOI: 10.1039/a706832h
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Reactive scattering of ground-state and electronically excited oxygen atoms on a liquid hydrocarbon surface

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Cited by 64 publications
(118 citation statements)
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“…Corresponding average fractions of available energy appearing in OH translation (f t ) and rotation (f rot ) and deposited in the surface (f sur ). It is assumed throughout that the O( 3 P) atoms which react carry an average translational energy of 21 mechanistically the H-abstraction reactions with squalane and squalene are very similar. The significant differences in rotational energy release (see Fig.…”
Section: Discussionmentioning
confidence: 99%
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“…Corresponding average fractions of available energy appearing in OH translation (f t ) and rotation (f rot ) and deposited in the surface (f sur ). It is assumed throughout that the O( 3 P) atoms which react carry an average translational energy of 21 mechanistically the H-abstraction reactions with squalane and squalene are very similar. The significant differences in rotational energy release (see Fig.…”
Section: Discussionmentioning
confidence: 99%
“…Examples include the reactions with F, 17,18 Cl, 19 O( 1 D), 20 and O( 3 P). [21][22][23][24][25][26][27][28][29] Of these, the O( 3 P) + squalane reaction is the most thoroughly characterised. The reaction produces OH radicals by abstraction of a hydrogen atom.…”
Section: Introductionmentioning
confidence: 99%
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“…Signal sizes were referenced against interleaved measurements of the well-studied standard, squalane. [32][33][34][35][36][37][38][39][40] To achieve the desired precision, the appearance profiles were averaged over typically ten sets of independent measurements over several different days for each mixture studied. They were corrected for a small background signal caused by a HONO impurity in the chamber by the procedure described previously.…”
Section: Reactive Atom Scatteringmentioning
confidence: 99%
“…13,14,35,36 Other gas-surface processes that could involve OH radicals include ion-mediated reactions 37 such as Process 5, which would produce OH at the surface, and Process 6, OH surface recombination to produce H 2 O 2 , 38 which would consume OH at the surface.…”
Section: Discussionmentioning
confidence: 99%