2003
DOI: 10.1515/jgth.2003.044
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Recognition of the simple groups L3(q) by element orders

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Cited by 32 publications
(31 citation statements)
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“…By (12) and (10), we have j − s > 8 > 2, 3; n − j − r > 8 > 2, 3; and n − s − r = (n − j − r) + (j − s) > 8 + 8 = 16. Thus (n − s − r, j − s) is an admissible pair and by induction we have n − s − r = n 1 + · · · + n k and j − s = n 1 + · · · + n k .…”
Section: [εN]mentioning
confidence: 92%
See 1 more Smart Citation
“…By (12) and (10), we have j − s > 8 > 2, 3; n − j − r > 8 > 2, 3; and n − s − r = (n − j − r) + (j − s) > 8 + 8 = 16. Thus (n − s − r, j − s) is an admissible pair and by induction we have n − s − r = n 1 + · · · + n k and j − s = n 1 + · · · + n k .…”
Section: [εN]mentioning
confidence: 92%
“…Let G be a proper cover for H of minimal order such that ω(H) = ω(G). By [12,Lemma 12], we may assume that G = N H, where H acts on the elementary abelian r-group N irreducibly. Suppose that this action is not absolutely irreducible.…”
Section: Lemmamentioning
confidence: 99%
“…. , ϕ 5 in this block are the 2-reductions of the generalized characters χ 1 , 6 , and χ 8 which take on h the values 1, −1, 0, 0, and 0, respectively. Hence we may assume that ϕ = ϕ 2 .…”
Section: Table 4 the Ordinary Charactersmentioning
confidence: 99%
“…(16) Suppose that P ∼ = G 2 (q), 2 < q ≡ ε mod 3, ε = ±1. In this case we have q 2 − εq + 1 = 2 p − 1.…”
Section: Proof Of the Main Theoremmentioning
confidence: 99%