“…However, when 6-ethoxycarbonyl-7-methyl-2-phenylpyrazolo[1,5-a]pyrimidine (78) was boiled for 20 h with a 15% water-alcohol solution of potassium hydroxide, 7-methyl-2-phenylpyrazolo[1,5-a]pyrimidine (84) and not the expected Kost-Sagitullin rearrangement product was formed. An attempt at rearrangement of the 6-acetyl derivative 81 under the same conditions also did not lead to the corresponding Kost-Sagitullin recyclization product; the only isolated substance was the same pyrazolo-[1,5-a]pyrimidine 84 [120,121]. The formation of one and the same compound 84 in the two reactions can probably be explained by the occurrence of a series of successive recyclization transformations, including opening of the pyrimidine ring, its cyclization, and decarboxylation.…”