2013
DOI: 10.1093/imrn/rnt111
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Regularity and Fast Escaping Points of Entire Functions

Abstract: Let f be a transcendental entire function. The fast escaping set A(f ), various regularity conditions on the growth of the maximum modulus of f , and also, more recently, the quite fast escaping set Q(f ) have all been used to make progress on fundamental questions concerning the iteration of f . In this paper we establish new relationships between these three concepts.We prove that a certain weak regularity condition is necessary and sufficient for Q(f ) = A(f ) and give examples of functions for which Q(f ) … Show more

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Cited by 19 publications
(26 citation statements)
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“…We remark that Beurling proved this estimate with the first constant on the right‐hand side equal to π/(42), but for simplicity we use the value 1/2 here. We also remark that further applications of Lemma were given in .…”
Section: Applications Of a Results Of Beurlingmentioning
confidence: 96%
“…We remark that Beurling proved this estimate with the first constant on the right‐hand side equal to π/(42), but for simplicity we use the value 1/2 here. We also remark that further applications of Lemma were given in .…”
Section: Applications Of a Results Of Beurlingmentioning
confidence: 96%
“…In an earlier paper [23], we saw other families of functions of order less than 1/2 for which Q(f ) contains a spider's web. For many of these, Q(f ) = A(f ) (see [21]), but there are examples for which Q(f ) contains A(f ) strictly (see [22]).…”
Section: Spiders' Webs In V (F ) and Q(f )mentioning
confidence: 99%
“…In this context, Rippon and Stallard introduced the quite fast escaping set Q(f ) in [17], which is defined as follows:…”
Section: 2(b)])mentioning
confidence: 99%
“…The function f in [17, Example 6.1] was found by first constructing a real, increasing, convex function φ with certain properties and then using a result of Clunie and Kövari from [7] (see [17,Lemma 6.3]) in order to obtain a transcendental entire function f such that ψ(t) = log M(e t ) ∼ φ(t). Let µ(t) = exp(t 1/2 ), t ≥ 0.…”
mentioning
confidence: 99%