2008
DOI: 10.1515/crelle.2008.050
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Relative Galois module structure of rings of integers of absolutely abelian number fields

Abstract: Abstract. Let L/K be an extension of number fields where L/Q is abelian. We define such an extension to be Leopoldt if the ring of integers O L of L is free over the associated order A L/K . Furthermore we define an abelian number field K to be Leopoldt if every finite extension L/K

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Cited by 5 publications
(5 citation statements)
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“…Moreover, Hom Λ (X, Y ) is a (left) End Λ (Y )-lattice in Hom A (KX, KY ) via post-composition. The following result is a generalisation of [Joh08, Proof. Let f ∈ Hom Λ (X, Y ).…”
Section: 2mentioning
confidence: 86%
“…Moreover, Hom Λ (X, Y ) is a (left) End Λ (Y )-lattice in Hom A (KX, KY ) via post-composition. The following result is a generalisation of [Joh08, Proof. Let f ∈ Hom Λ (X, Y ).…”
Section: 2mentioning
confidence: 86%
“…At the same time, Martinet proved that every quaternion extension of degree 8 over Q that is wildly ramified is such that O L is free over its associated order [123], which is not always true when the extension is tamely ramified [124]. [112] is interesting also because it gathers several properties of associated orders that might be very useful, some of them are originally issued from [48] and [57]. For example, the next two propositions show how associated orders in composite fields and subfields can be determined under certain additional assumptions, which sometimes permits the reduction of the problem to simpler extensions:…”
Section: Classical Galois Module Theory For Number Fieldsmentioning
confidence: 99%
“…[48], Lem. 6 -[112], Cor.2.5). -Let L/K and M/K be Galois extensions of number fields with K ⊂ M ⊂ L and L/M at most tamely ramified.…”
mentioning
confidence: 99%
“…(A simplified proof of this result can be found in [18].) More generally, we say that a number field K is Leopoldt if, for every finite abelian extension L/K, the ring of integers O L is free over A L/K (note that this differs from the definition of Leopoldt given in [15]). Since A L/K = O K [G] if and only if L/K is tame, Leopoldt's Theorem implies the celebrated Hilbert-Speiser Theorem: Every tame finite abelian extension L of Q has a normal integral basis, that is, O L is free as a Z[G]-module.…”
Section: Introductionmentioning
confidence: 99%