2017
DOI: 10.1007/978-3-319-62127-2_2
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Replica Placement on Bounded Treewidth Graphs

Abstract: We consider the replica placement problem: given a graph and a set of clients, place replicas on a minimum set of nodes to serve all the clients; each client is associated with a request and maximum distance that it can travel to get served; there is a maximum limit (capacity) on the amount of request a replica can serve. The problem falls under the general framework of capacitated set cover. It admits an O(log n)-approximation and it is NP-hard to approximate within a factor of o(log n). We study the problem … Show more

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Cited by 1 publication
(2 citation statements)
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“…Another closely related problem to the CSC problem is the so-called Replica Placement problem. For the graphs of treewidth bounded by t, an O(t) approximation algorithm for this problem is presented in [1]. Finally, PTASes for the Capacitated Dominating Set, and Capacitated Vertex Cover problems on the planar graphs is presented in [6], under the assumption that the demands and capacities of the vertices are upper bounded by a constant.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…Another closely related problem to the CSC problem is the so-called Replica Placement problem. For the graphs of treewidth bounded by t, an O(t) approximation algorithm for this problem is presented in [1]. Finally, PTASes for the Capacitated Dominating Set, and Capacitated Vertex Cover problems on the planar graphs is presented in [6], under the assumption that the demands and capacities of the vertices are upper bounded by a constant.…”
Section: Introductionmentioning
confidence: 99%
“…Therefore, since M 1 and M 2 are disjoint, |M | = |M 1 | + |M | ≥ αN + 3(1−α)N Now, usingLemma 12, we conclude that the cost of an optimal solution to I is at least B + αN + 3(1−α)N It is easy to verify that the previous quantity is exactly equal to1 + 1−α 8(3p+1) • (B + N ), recalling that B = 3N • (4p + 1).Now, from Lemma 11, Corollary 1, and Corollary 2, we obtain the following APX-hardness result. For any constant c ≥ 1, there exists a constant c > 0 such that it is NP-hard to obtain a (1 + c , c)-approximation for the uniform capacitated version of MMCC 1.…”
mentioning
confidence: 99%