2017
DOI: 10.1017/s1446788717000283
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Representing Regular Pseudocomplemented Kleene Algebras by Tolerance-Based Rough sets

Abstract: We show that any regular pseudocomplemented Kleene algebra defined on an algebraic lattice is isomorphic to a rough set Kleene algebra determined by a tolerance induced by an irredundant covering.

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Cited by 15 publications
(7 citation statements)
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“…On the other hand, some three-valued algebraic structures have been represented as rough sets generated by one covering [57,59,58,4,37]. Our results are more general, since many-valued algebraic structures correspond to sequences of rough sets determined by a sequence of coverings.…”
Section: Tab 11: Structures and Operation Between Orthopairsmentioning
confidence: 85%
“…On the other hand, some three-valued algebraic structures have been represented as rough sets generated by one covering [57,59,58,4,37]. Our results are more general, since many-valued algebraic structures correspond to sequences of rough sets determined by a sequence of coverings.…”
Section: Tab 11: Structures and Operation Between Orthopairsmentioning
confidence: 85%
“…In addition, we proved [9, Theorem 4.8] that RS (T ) is a completely distributive lattice if and only if T is induced by an irredundant covering. We also showed in [10] that if T is a tolerance induced by an irredundant covering, then RS (T ) forms a regular double pseudocomplemented lattice such that for any (A, B) ∈ RS (T ),…”
Section: Introductionmentioning
confidence: 89%
“…It is proved in [6] that when T is a tolerance induced by an irredundant covering of U , RS (T ) is a regular double p-algebra. Recall from [8], for example, that an algebra (L, ∨, ∧, * , + , 0, 1) is called a double p-algebra if (L, ∨, ∧, 0, 1) is a bounded lattice such that * is the pseudocomplement operation and + is the dual pseudocomplement operation on L. Note that this means that for all a ∈ A Boolean lattice is a bounded distributive lattice L such that each element a ∈ L has a complement a ′ which satisfies a ∧ a ′ = 0 and a ∨ a ′ = 1.…”
Section: Further Properties Of Rs (E T )mentioning
confidence: 99%
“…Obviously, each equivalence E on U is such that its equivalence classes U/E form an irredundant covering of U and that the "tolerance" induced by U/E is E. Tolerances induced by an irredundant covering of U play an important role in Section 4. It is known (see [6,7]) that if T is a tolerance induced by an irredundant covering, then this covering is {T (x) | T (x) is a block}. Lemma 2.13.…”
Section: Tolerances Induced By Coveringsmentioning
confidence: 99%
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