In this paper, we almost completely solve the existence of almost resolvable cycle systems with odd cycle length. We also use almost resolvable cycle systems as well as other combinatorial structures to give some new solutions to the Hamilton-Waterloo problem.
K E Y W O R D Salmost resolvable cycle system, Hamilton-Waterloo problem, 2-factorization
In this paper, we almost completely solve the existence of almost resolvable cycle systems with odd cycle length. We also use almost resolvable cycle systems as well as other combinatorial structures to give some new solutions to the Hamilton-Waterloo problem.
K E Y W O R D Salmost resolvable cycle system, Hamilton-Waterloo problem, 2-factorization
“…A factor of H is a spanning subgraph of H. Suppose G is a subgraph of H, a G-factor of H is a set of edge-disjoint subgraphs of H, each isomorphic to G. A G-factorization of H is a set of edge-disjoint G-factors of H. A C k -factorization of H is a partition of E(H) into C k -factors. Many papers introduced C k -factorization of K u [g], see [2,4,10,18,19,20,22,23]. Theorem 1.1.…”
Section: Introductionmentioning
confidence: 99%
“…For the case (m, n) ∈ {(3, 15), (5,15), (4,6), (4,8), (4,16), (8,16)}, see [1]. The existence of an HW(v; 4, n; α, β) for odd n ≥ 3 has been solved except possibly when v = 8n and α = 2, see [13,21,24].…”
In this paper, we almost completely solve the Hamilton-Waterloo problem with C 8 -factors and C m -factors where the number of vertices is a multiple of 8m.
“…We denote the cycle of length k by C k , the complete graph on v vertices by K v , and the complete u-partite graph with u parts of size g by K u [g]. A factor of a graph H is a spanning subgraph of H. Suppose G is a subgraph of a graph H, a G-factor of H is a set of edge-disjoint subgraphs of H, each isomorphic to G. And a G-factorization of H is a set of edge-disjoint G-factors of H. Many authors [2,4,15,16,18,19,25,26] have contributed to prove the following result. Theorem 1.1.…”
Section: Introductionmentioning
confidence: 99%
“…Theorem 1.1. There exists a C k -factorization of K u [g] if and only if g(u − 1) ≡ 0 (mod 2), gu ≡ 0 (mod k), k is even when u = 2, and (k, u, g) ∈ {(3, 3, 2), (3,6,2), (3,3,6), (6,2,6)}.…”
The Hamilton-Waterloo problem asks for a 2-factorization of K v (for v odd) or K v minus a 1-factor (for v even) into C m -factors and C n -factors. We completely solve the Hamilton-Waterloo problem in the case of C 3 -factors and C n -factors for n = 4, 5, 7.
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