Results of the troitsk experiment on the search for the electron antineutrino rest mass in tritium beta-decay

Neutrino mass problem: the state of the art

“…Comparison of (15) and (16) at m n 0 shows that K E e $ E 0 À E e , i.e. the Curie plot is a straight line intersecting the energy axis at E e E 0 (Fig.…”

“…Among the reviews close to the topics of the various sections in this paper we point out those by Zatsepin and Smirnov [5] and Muto and Klapdor [6] (the general properties of neutrinos), Gelmini and Roulet [7] and Boehm and Vogel [8] (neutrino masses), Wojcicki [9] (neutrino oscillations and the masses of n m and n t ), Moe and Vogel [10,11] and Shchepkin [12] (double beta decay), Borovo|¯and Khakimov [13] (experiments with reactor neutrinos), Weinheimer et al [14] and Belesev et al [15] (the mass of n e ), and Imshennik and Nadezhin [16] (Supernova 1987A). The values of some quantities are those accepted as of April 1997.…”

“…The second record-breaking (and even smaller) value of an upper bound on the mass ofñ e (mñ e`4 X35 eV) was obtained by Belesev et al [15] and Lobashev [78] at the Institute for Nuclear Research of the Russian Academy of Sciences in the city of Troitsk (Moscow region). The main idea of this experiment was suggested by Lobashev and Spivak [79], and the experimental devices are described in Ref.…”

Neutrino oscillation constraints on neutrinoless double-beta decay

“…Therefore, the observation of the effect of a neutrino mass in the experiments measuring the high-energy part of the β-spectrum of 3 H [52,53] would be an indication in favor of the neutrino spectrum (5.1) with an "inverted" mass hierarchy.…”

“…Also the values of the effective neutrino mass m( 3 H) measured in the experiments that investigate the high-energy part of the β-spectrum of 3 H [52,53] are different in the schemes A and B. In the scheme A we have m( 3 H) ≃ m 4 ≃ √ ∆m 2 , whereas in the scheme B the contribution of the term that depends on the heavy masses m 3 ≃ m 4 to the β-spectrum of 3 H is suppressed by the factor i=3,4 |U ei | 2 ≤ a 0 e .…”