2006
DOI: 10.1002/jgt.20191
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Retracts of box products with odd‐angulated factors

Abstract: Let G be a connected graph with odd girth 2κ + 1. Then G is a (2κ + 1)-angulated graph if every two vertices of G are connected by a path such that each edge of the path is in some (2κ + 1)-cycle. We prove that if G is (2κ + 1)-angulated, and H is connected with odd girth at least 2κ + 3, then any retract of the box (or Cartesian) product G H is S T where S is a retract of G and T is a connected subgraph of H. A graph G is strongly (2κ + 1)-angulated if any two vertices of G are connected by a sequence of (2κ … Show more

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Cited by 3 publications
(6 citation statements)
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“…Note that (A&B) k → (A B) k → A B. However, A B is an induced subgraph of (A&B) 2 , so A B is a retract of (A&B) k for k ≥ 2. Recall that A B is also a core.…”
Section: Applications To Odd-angulated Graphsmentioning
confidence: 93%
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“…Note that (A&B) k → (A B) k → A B. However, A B is an induced subgraph of (A&B) 2 , so A B is a retract of (A&B) k for k ≥ 2. Recall that A B is also a core.…”
Section: Applications To Odd-angulated Graphsmentioning
confidence: 93%
“…See also Klavžar [6], which corrected some errors in [8]. Recently, Che and Collins [2] extended this result to the box product G H with one factor that is (2k + 1)-angulated or strongly (2k + 1)-angulated. They proved the following result.…”
Section: Introductionmentioning
confidence: 91%
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