“…Equating the elements (1,2), (2,2), (3,1), (3,3) and (3,2) gives the following equations: 11 12 = This case admits a similar analysis to the previous one: some unknowns must be solved in terms of the others and, in particular, we can choose to solve all the unknowns in terms of the variables φ 1B and y B to deal with simpler equations. However, since r 31 = r 32 = 0, a restriction is lost because Eq.…”