“…In either case, θ(e 1 ) = θ(d 1 ) −2 has order n/2, and so σ(ker θ) has two empty period cycles. With regard to orientability, ker θ always contains a non-orientable word, such as d (3,4), (3,5), (3,6) and (4,4). In all cases, n = lcm(m 1 , m 2 , 2), since C n is generated by elements of orders m 1 , m 2 and 2; for example, in the first case m = n or m = n/2, with the latter value occurring only when n/2 is odd.…”