2013
DOI: 10.1016/j.jalgebra.2013.01.021
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Rings and modules which are stable under automorphisms of their injective hulls

Abstract: It is proved, among other results, that a prime right nonsingular ring (in particular, a simple ring) R is right self-injective if R R is invariant under automorphisms of its injective hull. This answers two questions raised by Singh and Srivastava, and Clark and Huynh. An example is given to show that this conclusion no longer holds when prime ring is replaced by semiprime ring in the above assumption. Also shown is that automorphism-invariant modules are precisely pseudo-injective modules, answering a recent… Show more

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Cited by 73 publications
(60 citation statements)
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“…Thus, the result of Dickson and Fuller states that if R is a finite-dimensional algebra over a field F with more than two elements, then R is of right invariant module type if and only if every indecomposable right R-module is automorphism-invariant. Examples of automorphism-invariant modules which are not quasi-injective, can be found in [5] and [13]. And recently, it has been shown in [5] that a module M is automorphism-invariant if and only if every monomorphism from a submodule of M extends to an endomorphism of M. For more details on automorphism-invariant modules, see [5], [9], [11], and [12].…”
Section: Introductionmentioning
confidence: 99%
“…Thus, the result of Dickson and Fuller states that if R is a finite-dimensional algebra over a field F with more than two elements, then R is of right invariant module type if and only if every indecomposable right R-module is automorphism-invariant. Examples of automorphism-invariant modules which are not quasi-injective, can be found in [5] and [13]. And recently, it has been shown in [5] that a module M is automorphism-invariant if and only if every monomorphism from a submodule of M extends to an endomorphism of M. For more details on automorphism-invariant modules, see [5], [9], [11], and [12].…”
Section: Introductionmentioning
confidence: 99%
“…Example 2.2. Consider the ring R consisting of all eventually constant sequences of elements from F 2 (see [10,Example 9]). Clearly, R is a commutative automorphism-invariant ring as the only automorphism of its injective envelope is the identity automorphism.…”
Section: An Examplementioning
confidence: 99%
“…Proof. By [10,Theorem 3], there exists a decomposition R R = A ⊕ B ⊕ C where A ∼ = B and the module C is square-free which is orthogonal to A ⊕ B. Let X := A ⊕ B and Y := C. Now we proceed to show that X is square-full.…”
Section: Some Characterizations Of A-ringsmentioning
confidence: 99%
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