“…Consider now (29), and use a Schur complement to get e βπ΄ π π π e βπ΄π β πΌ β πΎ π (π)πΆ π π Ξ( π) πΌ β πΎ π (π)πΆ π > 0, (37) namely π (π, π) > 0, β(π, π) β C. Since C is compact, we may define the scalar (independent of π):…”