Let E be an elliptic curve defined over an algebraically closed field k whose characteristic is not 2 or 3. Let τ be a translation automorphism of E that is not of order 2. In a previous paper we studied an algebra A = A(E, τ ) that depends on this data:where S(E, τ ) is the 4-dimensional Sklyanin algebra associated to (E, τ ), M2(k) is the ring of 2 × 2 matrices over k, and Γ is (Z/2) × (Z/2) acting in a particular way as automorphisms of S and M2(k). The action of Γ on S is compatible with the translation action of the 2-torsion subgroup E[2] on E. Following the ideas and results in papers of Artin-Tate-Van den Bergh, Smith-Stafford, and Levasseur-Smith, this paper examines the line modules, point modules, and fat point modules, over A, and their incidence relations. The right context for the results is non-commutative algebraic geometry: we view A as a homogeneous coordinate ring of a non-commutative analogue of P 3 that we denote by Proj nc (A). Point modules and fat point modules determine "points" in Proj nc (A). Line modules determine "lines" in Proj nc (A). Line modules for A are in bijection with certain lines in P(A * 1 ) ∼ = P 3 and therefore correspond to the closed points of a certain subscheme L of the Grassmannian G(1, 3). Shelton-Vancliff call L the line scheme for A. We show that L is the union of 7 reduced and irreducible components, 3 quartic elliptic space curves and 4 plane conics in the ambient Plücker P 5 , and that deg(L) = 20. The union of the lines corresponding to the points on each elliptic curve is an elliptic scroll in P(A * 1 ). Thus, the lines on that elliptic scroll are in natural bijection with a corresponding family of line modules for A.2010 Mathematics Subject Classification. 16E65, 16S38, 16T05, 16W50. Key words and phrases. Sklyanin algebras, elliptic algebras, line modules.2. The 4-dimensional Sklyanin algebras S(E, τ ) 2.1. Definition of the Sklyanin algebra. Always, α 1 , α 2 , α 3 are fixed elements in k − {0, ±1} such that α 1 + α 2 + α 3 + α 1 α 2 α 3 = 0. We often write α = α 1 , β = α 2 , and γ = α 3 . As in [9, §6], we fix a, b, c, i ∈ k such that a 2 = α, b 2 = β, c 2 = γ, and i 2 = −1.