1976
DOI: 10.1029/jb081i032p05679
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Rupture velocity of plane strain shear cracks

Abstract: Propagation of plane strain shear cracks is calculated numerically by using finite difference equations with second-order accuracy. The rupture model, in which stress drops gradually as slip increases, combines two different rupture criteria: (1) slip begins at a finite stress level; (2) finite energy is absorbed per unit area as the crack advances. Solutions for this model are nonsingular. In some cases there may be a transition from rupture velocity less than Rayleigh velocity to rupture velocity greater tha… Show more

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Cited by 935 publications
(981 citation statements)
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“…Here, rupture propagation is below the Rayleigh wave speed c r (for u = 0.483 , c r 0.95c s ) until about the last time step plotted in Figure 3b where the rupture begins a transition to rupture propagation beyond the shear wave speed (so-called supershear rupture), first in the downslope direction and shortly followed by a transition in the upslope direction (not shown). (Andrews 1976) and here r = 0.32 (note r = 1 / (1 + S) where S is a similar measure commonly used in earthquake rupture studies).…”
Section: Finite Element Model Of a Dynamic Subsurface Rupturementioning
confidence: 99%
“…Here, rupture propagation is below the Rayleigh wave speed c r (for u = 0.483 , c r 0.95c s ) until about the last time step plotted in Figure 3b where the rupture begins a transition to rupture propagation beyond the shear wave speed (so-called supershear rupture), first in the downslope direction and shortly followed by a transition in the upslope direction (not shown). (Andrews 1976) and here r = 0.32 (note r = 1 / (1 + S) where S is a similar measure commonly used in earthquake rupture studies).…”
Section: Finite Element Model Of a Dynamic Subsurface Rupturementioning
confidence: 99%
“…Moreover, it is doubtful that local stress state is one of pure in-plane shear despite the fact that it prevails globally at distances far away from the crack tip. Should the main crack be macroscopic and the nucleated crack be microscopic [2], then there is no valid reason why the same event would not occur for an in-plane extensional crack. Equally unconvincing is the explanation offered by the finite cohesive traction shear crack model [3] where a finite peak shear stress was developed ahead of the tip.…”
Section: Introductionmentioning
confidence: 99%
“…However, a lot of engineering structures are under the conditions of dynamic loadings and the static theory can't effectually III resolve a series of dynamic queries, so it is indispensable to study the fracture dynamics problems (Sih, 1968;Kostrov, 1964;Freund, 1998;Sih and MacDonald, 1974;Srolovitz and Source, 1997). A lot of researches on mode III crack dynamic propagation problems were performed cautiously (Freund, 1998;Sih and MacDonald, 1974;Srolovitz and Source, 1997;Gao, 1996;Andrew, 1976;Rosakis et al, 1999;Tang and Sih, 2004). In view of the complexity, cockamamie and difficulty in mathematical operations, fracture dynamics problems are not investigated enough thoroughly (Sih, 1968;Kostrov, 1964;Freund, 1998;Sih and MacDonald, 1974;Srolovitz and Source, 1997;Broberg, 1960;RubinGonzalea and Mason, 2000) and numerical solutions acquired (Sih and MacDonald, 1974;Sih, 1973;1991;Fedelinski et al, 1997;Wang et al, 1992;Knauss, 1987;Wang, 1992;Ranjith and Narasimhan, 1996) were much more than analytical solutions (Nian-Chun et al, 2004;2005;2006).…”
Section: Introductionmentioning
confidence: 99%