“…We will show by induction on j that Q(j) holds for any 3 ≤ j ≤ k. j = 3 Assume that i 3 > 4. Then τ 3i 3 = 0 by (5). But τ 31 = 0 by P (3), whence det(σ 1,3,i 3 ...,i k 1,3,i 3 ...,i k ) − det(τ 1,3,i 3 ...,i k 1,3,i 3 ...,i k ) = τ 23 det(σ 3,i 3 ...,i k 1,i 3 ...,i k ) = 0.…”