Abstract:Contents 0. Introduction 1 0.1. Hereditarily James Tree spaces 3 0.2. Saturated extensions 7 0.3. The attractors method 10 1. Strictly singular extensions with attractors 15 2. Strongly strictly singular extensions 24 3. The James tree space JT F2 . 32 4. The space (X F2 ) * and the space of the operators L((X F2 ) * ) 40 5. The structure of X * F2 and a variant of X F2 46 6. A nonseparable HI space with no reflexive subspace 52 7. A HJT space with unconditionally and reflexively saturated dual 63 Appendix A. … Show more
“…For an arbitrary seminormalized weakly null sequence in Z X we can pass to a subsequence satisfying the same (1), (2) and (3) as in the proof of Proposition 7. Since Remark 2 is the same are Remark 1 with a different quotient map, by mimicking the proof of Proposition 7 it can be shown that this subsequence in Cesaro summable, as required.…”
Section: Proof Let E ⊂ N Be An Interval and (Bmentioning
confidence: 99%
“…In [2] a Banach space Z is constructed satisfying the assumptions of Theorem 21. Z * is the desired space.…”
Section: Spaces Not Admitting Quotients With Separable Dualsmentioning
confidence: 99%
“…Namely, we observe that a space constructed in [2] does not admit as quotient any space with separable dual. This solves a question posed in [13, page 86, Remark IV.1].…”
Section: Introductionmentioning
confidence: 98%
“…(2) There is a separable space Y not admitting any ℓ p for 1 ≤ p < ∞ or c 0 as a spreading model such that X is a quotient of Y .…”
Abstract. It is shown that for each separable Banach space X not admitting ℓ 1 as a spreading model there is a space Y having X as a quotient and not admitting any ℓp for 1 ≤ p < ∞ or c 0 as a spreading model.We also include the solution to a question of W.B. Johnson and H.P. Rosenthal on the existence of a separable space not admitting as a quotient any space with separable dual.
“…For an arbitrary seminormalized weakly null sequence in Z X we can pass to a subsequence satisfying the same (1), (2) and (3) as in the proof of Proposition 7. Since Remark 2 is the same are Remark 1 with a different quotient map, by mimicking the proof of Proposition 7 it can be shown that this subsequence in Cesaro summable, as required.…”
Section: Proof Let E ⊂ N Be An Interval and (Bmentioning
confidence: 99%
“…In [2] a Banach space Z is constructed satisfying the assumptions of Theorem 21. Z * is the desired space.…”
Section: Spaces Not Admitting Quotients With Separable Dualsmentioning
confidence: 99%
“…Namely, we observe that a space constructed in [2] does not admit as quotient any space with separable dual. This solves a question posed in [13, page 86, Remark IV.1].…”
Section: Introductionmentioning
confidence: 98%
“…(2) There is a separable space Y not admitting any ℓ p for 1 ≤ p < ∞ or c 0 as a spreading model such that X is a quotient of Y .…”
Abstract. It is shown that for each separable Banach space X not admitting ℓ 1 as a spreading model there is a space Y having X as a quotient and not admitting any ℓp for 1 ≤ p < ∞ or c 0 as a spreading model.We also include the solution to a question of W.B. Johnson and H.P. Rosenthal on the existence of a separable space not admitting as a quotient any space with separable dual.
“…Indeed, if X is QHI restricted to block-subspaces, then no quotient of X by an FDD-block subspace can contain an unconditional basic sequence, and therefore X must contain a quotient of a subspace with the stronger "angle zero" property. [1], the distinction between general quotient spaces and quotients by FDD-block subspaces may be essential: there exists a separable dual space X with a Schauder basis such that quotients with w * -closed kernels are HI, yet every quotient has a further quotient isomorphic to l 2 . Since FDD-block subspaces of X are w * -closed, this space has the restricted QHI property, but it is not QHI by the l 2 -saturation property.…”
Abstract. A Banach space X with a Schauder basis is defined to have the restricted quotient hereditarily indecomposable property if X/Y is hereditarily indecomposable for any infinite-codimensional subspace Y with a successive finite-dimensional decomposition on the basis of X. The following dichotomy theorem is proved: any infinite-dimensional Banach space contains a quotient of a subspace which either has an unconditional basis, or has the restricted quotient hereditarily indecomposable property.
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