1989
DOI: 10.1016/0022-1236(89)90050-5
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Schur products and matrix completions

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Cited by 106 publications
(86 citation statements)
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“…However, it is simpler to prove Theorem 3.1 directly. Theorem 3.1(a) is due to Haagerup (unpublished); it was proved, in a more general form (involving partial matrices), in [13,Theorem 3.2]; it was also derived by Ando and Okubo, using the identity above, from the main result in [2], which is Theorem 3.2(a). All these proofs are based on Arvenson's Extension Theorem for positive maps on C* algebras.…”
Section: Hadamard Productsmentioning
confidence: 97%
“…However, it is simpler to prove Theorem 3.1 directly. Theorem 3.1(a) is due to Haagerup (unpublished); it was proved, in a more general form (involving partial matrices), in [13,Theorem 3.2]; it was also derived by Ando and Okubo, using the identity above, from the main result in [2], which is Theorem 3.2(a). All these proofs are based on Arvenson's Extension Theorem for positive maps on C* algebras.…”
Section: Hadamard Productsmentioning
confidence: 97%
“…If S a·b acts on X = B( 2 ), one can prove the above lemma by using the version of Stinespring's Extension Theorem for restricted Schur multipliers developed in [19]. However, the above proof has the advantages of being constructive and of working for arbitrary unconditional matrix spaces.…”
Section: Proof Of Theorem 11mentioning
confidence: 99%
“…We may assume D = 1. Let R ′ × C ′ be any finite subset of R × C. By [16,Th. 3.2], there exist vectors w c and v r of norm at most 1 in a Hilbert space H such that ϕ rc = w c , v r for every (r, c)…”
Section: Relative Schur Multipliersmentioning
confidence: 99%
“…If (a) holds, every sequence of signs ǫ ∈ {−1, 1} I is a Schur multiplier on S ∞ I . By a convexity argument, this implies that every bounded sequence is a Schur multiplier on S ∞ I , which may be extended to a Schur multiplier on S ∞ with the same norm by [16,Cor. 3.3].…”
Section: Sketch Of Proof (A) ⇒ (B)mentioning
confidence: 99%