2018
DOI: 10.19086/da.2750
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Schwartz-Zippel bounds for two-dimensional products

Abstract: We prove bounds on intersections of algebraic varieties in C 4 with Cartesian products of finite sets from C 2 , and we point out connections with several classic theorems from combinatorial geometry. Consider an algebraic variety X ⊂ C 4 of degree d, such that not all polynomials that vanish on X are of the formwhere G, H, K, L are polynomials and G and K are not constant. Let P, Q ⊂ C 2 be finite sets of size n. If X has dimension one or two, then we prove |X ∩ (P × Q)| = O d (n), while if X has dimension th… Show more

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Cited by 3 publications
(4 citation statements)
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“…Theorem 1.1 replaces this combinatorial condition with an algebraic condition on F . An incidence bound with a similar (but different) algebraic condition was obtained in [12], for point sets and curve sets that do not have this Cartesian product structure.…”
Section: Introductionmentioning
confidence: 79%
“…Theorem 1.1 replaces this combinatorial condition with an algebraic condition on F . An incidence bound with a similar (but different) algebraic condition was obtained in [12], for point sets and curve sets that do not have this Cartesian product structure.…”
Section: Introductionmentioning
confidence: 79%
“…Remark 4. The formulation of Theorem 3 is inspired by the main results and the proofs in [15,18,17]. In these papers one is interested in a bound on the cardinality of a set of the form V ∩ (P × Q), where V ⊂ R 4 is an algebraic variety of fixed degree, and each of P, Q is a finite subset of R 2 (of arbitrarily large cardinality).…”
Section: Main Resultmentioning
confidence: 99%
“…The study of such questions was initiated by Nassajian Mojarrad et al [33]. Even analogues of the Schwartz-Zippel lemma become more complicated: The easiest case would be a bound of the form |X ∩ (P × Q)| for a variety X ⊂ C 4 and finite sets P, Q ⊂ C 2 , but there are varieties for which no non-trivial bound holds.…”
Section: Two-dimensional Productsmentioning
confidence: 99%
“…We say that a variety X ⊂ C 4 is Cartesian if every polynomial vanishing on X is Cartesian with the same G, K. For a Cartesian variety X, we can have |X ∩ (P × Q)| = |P ||Q|, since we can take P ⊂ Z(G) and Q ⊂ Z(K) to get P × Q ⊂ X. It is proved in [33] that if X is not Cartesian, then one can obtain non-trivial upper bounds on |X ∩ (P × Q)|. As a consequence, we obtain the following lower bound on the number of distinct values of a polynomial map F = (F 1 , F 2 ) : C 2 × C 2 → C 2 .…”
Section: Two-dimensional Productsmentioning
confidence: 99%