“…The only difference is that, whilst the angular velocity is the same for all orbits in the SHO, in the Kerr system it is conserved per orbit, but monotonically increasing as a function of the distance from the origin. Using (15), it is also easy to show that the classical action for the Kerr system as obtained from the flow above is given by S Kerr (q (q, p), q, t) = 1 4 ω(q, p) t + 2 p q(cos [ω(q, p) t] − 1) + (p 2 − q 2 ) sin [ω(q, p) t] , (66) while the symmetric action in ( 27) is just…”