“…Instead, we approximated r cavity,CH 4 as r cavity,CH 4 = 1 / 2 r cavity,Kr + 1 / 2 r cavity,Xe , because predicted gas–water radial distribution functions indicate that the effective radius of CH 4 in our simulations is intermediate between those of Kr and Xe. The resulting values of r cavity (calculated with r O = 1.4 Å) for He, H 2 , Ne, Ar, Kr, CH 4 , and Xe are 2.790, 2.970, 2.793, 3.082, 3.212, 3.308, and 3.405 Å, respectively. For CO 2 , we calculated the probability that two randomly placed spheres of radius r cavity = 1 / 2 σ Oc–Oc + r O = 2.917 Å (where O c is a CO 2 oxygen atom) separated by the same distance as the two oxygen atoms in CO 2 (2.3 Å) would contain no atom.…”