Abstract:Abstract. Using a new factor chain argument, we show that 5 does not divide an odd perfect number indivisible by a sixth power. Applying sieve techniques, we also find an upper bound on the smallest prime divisor. Putting this together we prove that an odd perfect number must be divisible by the sixth power of a prime or its smallest prime factor lies in the range 10 8 < p < 10 1000 . These results are generalized to much broader situations.
“…To prove Inequality 46 we then add our inequalities as follows: 4 ||N then one must have at least one prime which is not the special prime raised to at least the 6th power, and hence have u ≥ 1. We thus may adjust the above equations slightly: If (N, 55) = 1, we have instead of 47, we have ω = s + t + u − 1 and f 5 = f 11 = 0.…”
Let N be an odd perfect number. Let ω(N ) be the number of distinct prime factors of N and let Ω(N ) be the total number of prime factors of N . We prove that if (3, N ) = 1, then 302 113 ω− 286 113 ≤ Ω. If 3|N , then 66 25 ω − 5 ≤ Ω. This is an improvement on similar prior results by the author which was an improvement of a result of Ochem and Rao. We also establish new lower bounds on ω(N ) in terms of the smallest prime factor of N and establish new lower bounds on N in terms of its smallest prime factor.
“…To prove Inequality 46 we then add our inequalities as follows: 4 ||N then one must have at least one prime which is not the special prime raised to at least the 6th power, and hence have u ≥ 1. We thus may adjust the above equations slightly: If (N, 55) = 1, we have instead of 47, we have ω = s + t + u − 1 and f 5 = f 11 = 0.…”
Let N be an odd perfect number. Let ω(N ) be the number of distinct prime factors of N and let Ω(N ) be the total number of prime factors of N . We prove that if (3, N ) = 1, then 302 113 ω− 286 113 ≤ Ω. If 3|N , then 66 25 ω − 5 ≤ Ω. This is an improvement on similar prior results by the author which was an improvement of a result of Ochem and Rao. We also establish new lower bounds on ω(N ) in terms of the smallest prime factor of N and establish new lower bounds on N in terms of its smallest prime factor.
“…For odd perfect numbers, Euler obtained a necessary condition for the existence (see [5]). In recent years, there have been many papers for odd perfect numbers having to do with the conjecture that there exists no odd perfect numbers (see [2,3,4,7,12]). Until now, the conjecture has not been proved.…”
Abstract. Let α be a positive integer, and let p 1 , p 2 be two distinct prime numbers with p 1 < p 2 . By using elementary methods, we give two equivalent conditions of all even near-perfect numbers in the form 2 α p 1 p 2 and 2 α p 2 1 p 2 , and obtain a lot of new near-perfect numbers which involve some special kinds of prime number pairs. One kind is exactly the new Mersenne conjecture's prime number pair. Another kind has the form, where the former is a Mersenne prime and the latter's behavior is very much like a Fermat number.
We shall prove that ifis an odd perfect number such that p, q 1 , . . . , q r−1 are distinct primes, p ≡ α ≡ 1 (mod 4) and t divides 2β i + 1 for all i = 1, 2, . . . , r − 1, then t 5 divides N , improving an eighty-year old result of Kanold.
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