“…We will divide the proof of the lemma in the following cases: 1) α = (α 2 + 2a − 1, α 2 , a, a − 1, 1) with α 2 > 2a and a ≥ 4, 2) all other cases. Case 2) will be divided in subcases corresponding to the different cases of the proof of Theorem 1.6 of [2]. 1) For α = (α 2 + 2a − 1, α 2 , a, a − 1, 1) with α 2 > 2a and a ≥ 4 let β := (α 2 + 2a, 3, 1 α 2 +2a−4 ).…”