1971
DOI: 10.1063/1.1665464
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Simple Procedure for Determining the Number of Components of an Irreducible Tensor

Abstract: We show that the number of linearly independent components of a tensor in n dimensions with specified symmetry properties is given by a polynomial in n. This polynomial can be determined in a simple way from the Young diagram associated with the tensor.

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Cited by 5 publications
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“…The polynomial (4) with a natural number t appeared in [6]: the dimension of the space of tensors of rank t possessing a symmetry of type X is equal to (i/n!)d~P~(O. This result #This result was obtained earlier in [5].…”
Section: H: H~' L(t-i-~-]) (4)mentioning
confidence: 57%
See 1 more Smart Citation
“…The polynomial (4) with a natural number t appeared in [6]: the dimension of the space of tensors of rank t possessing a symmetry of type X is equal to (i/n!)d~P~(O. This result #This result was obtained earlier in [5].…”
Section: H: H~' L(t-i-~-]) (4)mentioning
confidence: 57%
“…follows from Theorem i and the fact that the indicated dimension is equal to the right-hand side of (6) …”
Section: H: H~' L(t-i-~-]) (4)mentioning
confidence: 86%