2009
DOI: 10.4169/002557009x478436
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Sines and Cosines of Angles in Arithmetic Progression

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Cited by 37 publications
(19 citation statements)
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“…Hence 2n+1 k=1 cos 2kπ 2n + 1 = 0, a fact that has been explained in this and other ways in this MAGAZINE [1,2]. Separating the last term gives 2n k=1 cos 2kπ 2n + 1 = −1.…”
mentioning
confidence: 79%
“…Hence 2n+1 k=1 cos 2kπ 2n + 1 = 0, a fact that has been explained in this and other ways in this MAGAZINE [1,2]. Separating the last term gives 2n k=1 cos 2kπ 2n + 1 = −1.…”
mentioning
confidence: 79%
“…From Figure 4 it is not totally clear whether the eigenvalue will remain away from zero as M increases. Indeed, for r = 0.2 roughly speaking we can see that: • for M ∈ [10,20] we have dϑM dM ≈ ϑ20−ϑ10 20−10 ≈ −10 −3 , • for M ∈ [50, 60] we have dϑM dM ≈ ϑ60−ϑ50 60−50 ≈ −6 · 10 −5 , • for M ∈ [110, 120] we have dϑM dM ≈ ϑ120−ϑ110 120−110 ≈ −1.5 · 10 −5 , from which we see that dϑM dM is increasing, but it also seems that it increases too slowly. In any case it is clear that, in the Neumann case, the eigenvalue ϑ M presents a remarkably different behaviour, for the locations D = mxe and D = uni.…”
Section: Comparison Between the Different Locationsmentioning
confidence: 94%
“…Let us fix M ≥ 1. The result follows from the fact that, for constants a ∈ R and b ∈ R, we have the identity whose proof can be found in[10]. Indeed, it is enough to observe that M k=1 cos(mc k ) =…”
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confidence: 88%
“…The following lemmas are necessary for proving the main results. We will use the well-known trigonometric identities (see [6][7][8][9])…”
Section: Auxiliary Factsmentioning
confidence: 99%