2004
DOI: 10.1016/j.ijsolstr.2004.02.004
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Singular integral equation method for the solution of multiple curved crack problems

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Cited by 22 publications
(13 citation statements)
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“…The distribution dislocation functions g 1 (t 1 ) and g 2 (t 2 ) respectively for the crack-1 (L 1 ), and for the crack-2 (L 2 ). Let N 1 (t 10 ) + iT 1 (t 10 ) be the tractions applied on the crack-1 at the point t 10 which obtained from g 1 (t 1 ) and g 2 (t 2 ) [11]. We obtain the singular integral equation for crack-1, which is…”
Section: Multiple Cracks Problem In Elastic Half Planementioning
confidence: 99%
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“…The distribution dislocation functions g 1 (t 1 ) and g 2 (t 2 ) respectively for the crack-1 (L 1 ), and for the crack-2 (L 2 ). Let N 1 (t 10 ) + iT 1 (t 10 ) be the tractions applied on the crack-1 at the point t 10 which obtained from g 1 (t 1 ) and g 2 (t 2 ) [11]. We obtain the singular integral equation for crack-1, which is…”
Section: Multiple Cracks Problem In Elastic Half Planementioning
confidence: 99%
“…where the tractions at at t 20 of crack-2 is N 2 (t 20 ) + iT 2 (t 20 ), and the integrals represented as in [11]. The singlevaluedness conditions for crack-1 and crack-2 are respectively, be given by FIGURE 2: Nondimensional SIFs at the crack tips A, B, C, and D for two cracks in series as in Fig.…”
Section: Multiple Cracks Problem In Elastic Half Planementioning
confidence: 99%
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“…Besides many analytical works have been done, the needs for numerical technique for solving such a problem still remains. Examples are, works by Chen et al (2003) and Chen, whom applied complex potential method to formulate the problems of multiple curved cracks into singular integral equations (Chen, 2004(Chen, , 2007 and a curved crack into hypersingular integral equation (Chen, 1993(Chen, , 2003. These equations were then solved numerically.…”
Section: Introductionmentioning
confidence: 99%
“…The curve length coordinate method is suggested to evaluate the singular or hypersingular integrals (Chen, 2003(Chen, , 2004. In the method, a substitution dt = (dt/ds)/ds is used, where t = x + iy is a complex variable and ds = [(dx) 2 + (dy) 2 ] 1/2 .…”
Section: Introductionmentioning
confidence: 99%