2019
DOI: 10.1016/j.jde.2018.11.006
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Singular optimal controls of stochastic recursive systems and Hamilton–Jacobi–Bellman inequality

Abstract: In this paper, we study the optimal singular controls for stochastic recursive systems, in which the control has two components: the regular control, and the singular control. Under certain assumptions, we establish the dynamic programming principle for this kind of optimal singular controls problem, and prove that the value function is a unique viscosity solution of the corresponding Hamilton-Jacobi-Bellman inequality, in a given class of bounded and continuous functions. At last, an example is given for illu… Show more

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Cited by 5 publications
(4 citation statements)
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References 67 publications
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“…Nevertheless, the reverse does not always hold. For instance, M = [1, 2) ⋃ (3,4] is 𝛾-convex, but it is neither convex set nor starlike relative to each of its point.…”
Section: Definitionmentioning
confidence: 99%
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“…Nevertheless, the reverse does not always hold. For instance, M = [1, 2) ⋃ (3,4] is 𝛾-convex, but it is neither convex set nor starlike relative to each of its point.…”
Section: Definitionmentioning
confidence: 99%
“…Now, we verify the optimality of the control ū(0) = ū(1) = (0, 0) * , ū( 2 Clearly, the set (f , 𝜎)(0, x(0), U(0)) is 𝛾-convex, the set (f , 𝜎)(1, x(1), U(1)) is convex, and for all x = (x 1 , x 2 , x 3 ) * ∈ R 3 ⧵ {0}, the sets (f , 𝜎)(1, x, U(1)) are starlike relative to the point f (1, x, ū(1)) + 𝜎(1, x, ū( 1))(w(2) − w(1)) = (0, 0, x 2 2 + x 2 2 (w(2) − w(1))) * . Taking into account these calculations, we have p(1) = q(0) = (0, 0, 0) * , further, we see that the control ū(t), t ∈ T is singular at t = 0 relative to the vector (û, v) ∈ U 0 (2) × U(0), where û = (0, û 2 (2)) * , û 2 (2) ∈ {−1, −0.5, 0} and v = (v 1 (0), 0) * , v 1 (0) ∈ [−1, 0] ∪ [2,3], and is also singular at t = 1 relative to the vector (û, ṽ) * ∈ U 0 (2) × U (1), where û = (0, û 2 (2)) * , û 2 (2) ∈ {−1, −0.5, 0} and ṽ = (ṽ 1 (1), ṽ2 (1)) * ∈ U (1). Set û = (0, −1) * , using ( 7), ( 10) and ( 31), (32), we get H xx (0, x(0), ū(0), p(1)) = H xx (1, x(1), ū(1), p(2)) = (0, 0, 0; 0, 0, 0; 0, 0, 0), H xx (2, x(2), ū(2), û(2), p(3)) = P(2) = (0, 0, 0; 0, −2, 0; 0, 0, 0), P(1) = (0, 0, 0; 0, 0, 0; 0, 0, 0), K(0, v, ū(0), û) = 0, K(1, ṽ, ū(1), û) = −2[ṽ 1 (1) + ṽ1 (1)(w(2) − w( 1))] 2 , L(1, ṽ, ū(1), û)[Δ v f (0) + Δ v 𝜎(0)(w(1) − w(0))] = ṽ2 (1)[v 1 (0) + v 1 (0)(w(1) − w(0))].…”
Section: Applicationsmentioning
confidence: 99%
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