“…Moreover, the G-orbits of the boundary arrows for A(sym d (O)) correspond exactly (in the sense of [GP19, Notation 3.13]) to the boundary arrows of A(O). It follows that even in our case, it is enough to show that the QP (Q G , W G ) of [GP19] is equal to (Q O , W O ), if we make appropriate choices. The fact that Q G = Q O is clear, as the two constructions both agree with the general construction presented in [RR85,Section 2].…”