2017
DOI: 10.2140/agt.2017.17.3621
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Slice implies mutant ribbon for odd 5–stranded pretzel knots

Abstract: A pretzel knot K is called odd if all its twist parameters are odd, and mutant ribbon if it is mutant to a simple ribbon knot. We prove that the family of odd, 5-stranded pretzel knots satisfies a weaker version of the Slice-Ribbon Conjecture: All slice, odd, 5stranded pretzel knots are mutant ribbon. We do this in stages by first showing that 5stranded pretzel knots having twist parameters with all the same sign or with exactly one parameter of a different sign have infinite order in the topological knot conc… Show more

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Cited by 8 publications
(10 citation statements)
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“…Since b 1 = 2, we know that c 1 > 2 which implies in turn that c 1 = 5, so that b 1 + c 1 = 7. From here an easy induction shows that the string L we are looking at is either [7,2,2,2], or [7 [s+1] , 2, 2, (3, 2 [4] ) [s] , 2]. Since this corresponds to b = [7 [s+1] , 5], we obtain the fractions…”
Section: (3)mentioning
confidence: 99%
See 2 more Smart Citations
“…Since b 1 = 2, we know that c 1 > 2 which implies in turn that c 1 = 5, so that b 1 + c 1 = 7. From here an easy induction shows that the string L we are looking at is either [7,2,2,2], or [7 [s+1] , 2, 2, (3, 2 [4] ) [s] , 2]. Since this corresponds to b = [7 [s+1] , 5], we obtain the fractions…”
Section: (3)mentioning
confidence: 99%
“…Montesinos family bounding surfaces of Euler characteristic 1 by several authors (see for example [28,29,18,7,25,26,31,11]).…”
Section: Figurementioning
confidence: 99%
See 1 more Smart Citation
“…Lecuona [Lec15] confirmed the slice-ribbon conjecture for all 3-stranded pretzel knots P (p, q, r) except for infinitely many 3-stranded pretzel knots of the form P (a, −a − 2, − (a+1) 2 2 ) for a ≥ 3 odd. There are further interesting results on the slice-ribbon conjecture for general pretzel knots and links (for example, see [Lon14,Bry17,AKPR18,KST20]).…”
Section: Introductionmentioning
confidence: 99%
“…The papers of Greene-Jabuka, Lecuona, and Choe-Park mentioned above sidestep mutant knots since there is no non-trivial mutation within the families they consider. However, the problem remains for more general families of knots and links if using double branched covers, as seen in the work of [Lon14,Bry17,Ace18].…”
Section: Introductionmentioning
confidence: 99%